# The currect voltage relation of diode is given by 1=(e1000V/T−1)mA, where the applied voltage V is in volt and the temperature T is in degree Kelvin. If a student makes an error measuring ±0.01V while measuring the current of 5mA at 300K, what will be error in the value of current in mA?

0.2 mA

0.2 mA

0.5 mA

0.05 mA

## The correct Answer is:A

## The current voltage relation of diode is - I=e1000VT−1

I+1=e1000VT

loge(I+1)=1000VT⇒d(I+1)I+1=1000TdV

⇒dII+1=1000TdV⇒dI(5+1)mA=1000300(0.01)

⇒dI=0.2mA

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